huyphancong2000 New member Xu 0 4/11/12 #1 Ai có thể giúp em bài này không?Thank nhiều (-5/6)^6.(6/5)^8:frog:
proboyvip1995 New member Xu 0 4/11/12 #3 \[(\frac{-5}{6})^{6}.(\frac{6}{5})^{8}\] \[=(\frac{-5}{6})^{6}.(\frac{6}{5})^{6+2}\] \[=(\frac{-5}{6})^{6}.(\frac{6}{5})^{6}.(\frac{6}{5})^{2}\] \[=(\frac{-5}{6}.\frac{6}{5})^{6}.(\frac{6}{5})^{2}\] \[=\frac{36}{25}\]
\[(\frac{-5}{6})^{6}.(\frac{6}{5})^{8}\] \[=(\frac{-5}{6})^{6}.(\frac{6}{5})^{6+2}\] \[=(\frac{-5}{6})^{6}.(\frac{6}{5})^{6}.(\frac{6}{5})^{2}\] \[=(\frac{-5}{6}.\frac{6}{5})^{6}.(\frac{6}{5})^{2}\] \[=\frac{36}{25}\]
proboyvip1995 New member Xu 0 4/11/12 #6 \[<=>9^{x}.9^{2} + 9^{x} = 9^{2}.(81 + 1)\] \[<=>9^{x}(9^{2} + 1) = 9^{2}.(9^{2} + 1)\] \[<=>9^{x} = 9^{2}\] \[<=>x = 2\]
\[<=>9^{x}.9^{2} + 9^{x} = 9^{2}.(81 + 1)\] \[<=>9^{x}(9^{2} + 1) = 9^{2}.(9^{2} + 1)\] \[<=>9^{x} = 9^{2}\] \[<=>x = 2\]