hai bạn trên làm đúng oy
Na[SUB]2[/SUB]CO[SUB]3[/SUB]+2HCl--->2NaCl+CO[SUB]2[/SUB]+H[SUB]2[/SUB]O
--------X mol----------\[\frac{x}{2}\]mol
KHCO[SUB]3[/SUB]+HCl--->KCl+CO[SUB]2[/SUB]+H[SUB]2[/SUB]O
-------y mol--------y mol
ta có:
x+y =0,2
\[\frac{x}{2}\]+y=0,12
=> x=0,16
y=0,04=>CM[SUB]KHCO[SUB]3[/SUB][/SUB]=\[\frac{0,04}{0,1}\]=0,4=>A