snowangel1103
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- Xu
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a) \[3(sin^4x+cos^4x)-2(sin^6+cos^6)=1\]
b) \[\frac{1-2sin^2x}{1+2sinxcosx}=\frac{1-tanx}{1+tanx}\]
c) \[\frac{sin^2\alpha-tan^2\alpha}{cos^2\alpha-cot^2\alpha}=tan^6\alpha\]
d) \[\frac{cos^3\alpha+sin^3\alpha}{1-sin\alpha.cos\alpha}=cos\alpha+sin\alpha\]
e) \[1-\frac{sin^2\alpha}{1+cot\alpha}-\frac{cos^2\alpha}{1+tan\alpha}=sin\alpha.cos\alpha\]
b) \[\frac{1-2sin^2x}{1+2sinxcosx}=\frac{1-tanx}{1+tanx}\]
c) \[\frac{sin^2\alpha-tan^2\alpha}{cos^2\alpha-cot^2\alpha}=tan^6\alpha\]
d) \[\frac{cos^3\alpha+sin^3\alpha}{1-sin\alpha.cos\alpha}=cos\alpha+sin\alpha\]
e) \[1-\frac{sin^2\alpha}{1+cot\alpha}-\frac{cos^2\alpha}{1+tan\alpha}=sin\alpha.cos\alpha\]