\[2\sqrt{2}sin\left(x-\frac{\pi }{12} \right)cosx=1 \Leftrightarrow \sqrt{2}\left[sin\left(2x-\frac{\pi }{12} \right)-sin\frac{\pi }{12} \right]=1 \Leftrightarrow sin\left(2x-\frac{\pi }{12} \right)-sin\frac{\pi }{12}=\frac{1}{\sqrt{2}} \Leftrightarrow sin\left(2x-\frac{\pi }{12} \right)=sin\frac{\pi }{4}+sin\frac{\pi }{12}=2sin\frac{\pi }{6}cos\frac{\pi }{12} \Leftrightarrow sin\left(2x-\frac{\pi }{12} \right)=cos\frac{\pi }{12}= sin\frac{5\pi }{12} \Leftrightarrow x=\frac{\pi }{4}+k\pi hay x=\frac{\pi }{3}+k\pi \left(k\in Z \right)\]