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<blockquote data-quote="hon$-n$ok-a1" data-source="post: 61708" data-attributes="member: 72749">tui la&#039; cả toi &amp;shy;wa do&#039; k bit co&#039; dung k hem&#039; kho&#039; that day M2CO3 +2HCL = 2MCL + H2O + CO2&nbsp; x&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; 2x&nbsp; &nbsp; &nbsp; &nbsp;&nbsp; 2x&nbsp; &nbsp; &nbsp; &nbsp;&nbsp; x&nbsp; &nbsp; &nbsp; &nbsp; xMHCO3 + HCL = MCL +H2O +CO2&nbsp; y&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; y&nbsp; &nbsp; &nbsp; &nbsp;&nbsp; y&nbsp; &nbsp; &nbsp;&nbsp; y&nbsp; &nbsp; &nbsp; &nbsp; yMCL&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; = MCL&nbsp;&nbsp; z&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; zN khi&#039; = x+y =0.4&nbsp;&nbsp; &nbsp; &nbsp; &nbsp;&nbsp; *phan&#039; 1: khi cho vao&#039; KOH ma&#039; tao muoi thi&#039; chung to&#039; HCL du&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; HCL + KOH = KCL + H2O&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0.1&nbsp; &nbsp; &nbsp; 0.1&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; N koh = 0.125 x 0.8 = 0.1&nbsp; &nbsp; &nbsp;&nbsp; *phan 2 :khi cho nua hon hop B t/d voi&#039; AgNO3 thi&#039;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; HCL + AgNO3 = AgCL + HNO3&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; 0.1&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0.1&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; (Do hai phan bang nhau nen mol HCL bang nhau )&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; MCL + AgNO3 = AgCL + MNO3&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; 0.38&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; 0.38&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (N AgCL=0.48 ma&#039; HCL tao ket tua 0.1 mol)&nbsp; &nbsp; &nbsp; &nbsp;&nbsp; vay ta co&#039;:2x + y +z = 0.38 x 2 = 0.76Ta co&#039; : 1 mol CO3&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; thi&#039; co&#039;&nbsp; &nbsp; 2 mol CL &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 1 mol CO3 , 1 mol H&nbsp; &nbsp;&nbsp; thi&#039; co&#039;&nbsp; &nbsp; 1 mol CL&nbsp; &nbsp; vay: 0.4mol CO3&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; thi&#039; co&#039;&nbsp;&nbsp; 0.4 x (2 + 3 ) : (1 +1)=0.6 mol CL&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; ma&#039; mol CL= 2x + y - y =2x =0.6 (do phai tru di mol cua H trong HCO3)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; VAY x=0.3 va&#039; ta dc y = 0.1 vay so mol axit la&#039;: 2x + y = 0.7&nbsp; &nbsp; Theo ĐLBTKL ta co&#039;: M hon hop + M axit phan ung = Mmuoi + M co2 +M h2o&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 43.71&nbsp; &nbsp; &nbsp; &nbsp;&nbsp; + 0.7 x 36.5&nbsp; &nbsp; &nbsp; &nbsp; =&nbsp; Mmuoi&nbsp; + 0.4 x 44 + 0.4 x 18&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; vay Mmuoi=&nbsp;&nbsp; 44.46 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ma&#039;: Mmuoi=(M +35.5) x (2x+y+z) = (M + 35.5) x 0.76 =44.46 vay M=23&nbsp; vay la&#039; Na</blockquote>

[QUOTE="hon$-n$ok-a1, post: 61708, member: 72749"] tui la' cả toi wa do' k bit co' dung k hem' kho' that day M2CO3 +2HCL = 2MCL + H2O + CO2 x 2x 2x x x MHCO3 + HCL = MCL +H2O +CO2 y y y y y MCL = MCL z z N khi' = x+y =0.4 *phan' 1: khi cho vao' KOH ma' tao muoi thi' chung to' HCL du HCL + KOH = KCL + H2O 0.1 0.1 N koh = 0.125 x 0.8 = 0.1 *phan 2 :khi cho nua hon hop B t/d voi' AgNO3 thi' HCL + AgNO3 = AgCL + HNO3 0.1 0.1 (Do hai phan bang nhau nen mol HCL bang nhau ) MCL + AgNO3 = AgCL + MNO3 0.38 0.38 (N AgCL=0.48 ma' HCL tao ket tua 0.1 mol) vay ta co':2x + y +z = 0.38 x 2 = 0.76 Ta co' : 1 mol CO3 thi' co' 2 mol CL 1 mol CO3 , 1 mol H thi' co' 1 mol CL vay: 0.4mol CO3 thi' co' 0.4 x (2 + 3 ) : (1 +1)=0.6 mol CL ma' mol CL= 2x + y - y =2x =0.6 (do phai tru di mol cua H trong HCO3) VAY x=0.3 va' ta dc y = 0.1 vay so mol axit la': 2x + y = 0.7 Theo ĐLBTKL ta co': M hon hop + M axit phan ung = Mmuoi + M co2 +M h2o 43.71 + 0.7 x 36.5 = Mmuoi + 0.4 x 44 + 0.4 x 18 vay Mmuoi= 44.46 ma': Mmuoi=(M +35.5) x (2x+y+z) = (M + 35.5) x 0.76 =44.46 vay M=23 vay la' Na [/QUOTE]

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