P pe_phd New member Xu 0 24/3/12 #1 x[SUP]4[/SUP]-3x[SUP]2[/SUP]+4x-3=0 x+1-căn(x-x[SUP]2[/SUP])=căn(x+x[SUP]2[/SUP]) căn(x+3)+căn(x+8)=5 2x-x[SUP]2[/SUP]+căn(6x[SUP]2[/SUP]-12x+7)=0 (x-1)[SUP]2[/SUP]+2lx-1l-8=0 lx[SUP]2[/SUP]-1l+lx[SUP]2[/SUP]-4l=3 (2x[SUP]2[/SUP])/[3-căn(9+2x)][SUP]2[/SUP]=x+9
x[SUP]4[/SUP]-3x[SUP]2[/SUP]+4x-3=0 x+1-căn(x-x[SUP]2[/SUP])=căn(x+x[SUP]2[/SUP]) căn(x+3)+căn(x+8)=5 2x-x[SUP]2[/SUP]+căn(6x[SUP]2[/SUP]-12x+7)=0 (x-1)[SUP]2[/SUP]+2lx-1l-8=0 lx[SUP]2[/SUP]-1l+lx[SUP]2[/SUP]-4l=3 (2x[SUP]2[/SUP])/[3-căn(9+2x)][SUP]2[/SUP]=x+9
N namtuckhn New member Xu 0 3/5/12 #2 1.<=> x[SUP]4 [/SUP] - 2x[SUP]2[/SUP] + 1 = x[SUP]2[/SUP] – 4x + 4 ó (x[SUP]2[/SUP] - 1)[SUP]2[/SUP] = (x – 2) [SUP]2[/SUP] 2.
1.<=> x[SUP]4 [/SUP] - 2x[SUP]2[/SUP] + 1 = x[SUP]2[/SUP] – 4x + 4 ó (x[SUP]2[/SUP] - 1)[SUP]2[/SUP] = (x – 2) [SUP]2[/SUP] 2.