M[SUB]A[/SUB] = 45,61 => 2 khí là CO[SUB]2[/SUB] và NO[SUB]2[/SUB]
2NO[SUB]2[/SUB] --> N[SUB]2[/SUB]O[SUB]4[/SUB]
Xét 1 mol A => nCO[SUB]2[/SUB] = 0,195 mol; nNO[SUB]2 [/SUB]= 0,805 mol
mA = mB => nB = 0,745 mol
=> nN[SUB]2[/SUB]O[SUB]4[/SUB] sinh ra = 0,255mol => nNO[SUB]2[/SUB] pư = 0,51 mol => HS = 63,35%