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<blockquote data-quote="bongtuyet96" data-source="post: 9161" data-attributes="member: 159343">[Giúp] Lượng giác 11<img src="https://codecogs.izyba.com/png.latex?6cos(\frac{5\pi }{2}-x)-2cos^{3}x=\frac{5sin4x.cosx}{2cos2x}" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?2sinx+sin3x+cosx=sin2x(2cosx+\sqrt{2})" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?\frac{1}{sinx}+\frac{1}{cosx}+\frac{\sqrt{2}cos(\frac{\pi }{4}-x)}{sin2x}=\frac{3}{sin2x}" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?sinx(1+cos2x)+sin2x=\sqrt{3}(1+cosx)" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?sin4x-cos4x=1+4(sinx-cosx)" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?sin^{4}x+cos^{4}x(x+\frac{\pi }{4})+sin^{4}(x-\frac{\pi }{4})=\frac{9}{8}" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?3cos4x-8cos^{6}x+2cos^{2}x+3=0" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?sin^{2}(x-\frac{\pi }{4}).tan^{2}x=sin^{2}\frac{x}{2}" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?\sqrt{\frac{1}{8cos^{2}x}}=sinx" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" /><img src="https://codecogs.izyba.com/png.latex?\frac{cos^{2}x(cosx-1)}{sinx+cosx}=2(1+sinx)" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" />.........................................................các bạn làm được phần nào thì làm thanks các bạn trước nhe!</blockquote>

[QUOTE="bongtuyet96, post: 9161, member: 159343"] [b][Giúp] Lượng giác 11[/b] [IMG]https://codecogs.izyba.com/png.latex?6cos(\frac{5\pi }{2}-x)-2cos^{3}x=\frac{5sin4x.cosx}{2cos2x}[/IMG] [IMG]https://codecogs.izyba.com/png.latex?2sinx+sin3x+cosx=sin2x(2cosx+\sqrt{2})[/IMG] [IMG]https://codecogs.izyba.com/png.latex?\frac{1}{sinx}+\frac{1}{cosx}+\frac{\sqrt{2}cos(\frac{\pi }{4}-x)}{sin2x}=\frac{3}{sin2x}[/IMG] [IMG]https://codecogs.izyba.com/png.latex?sinx(1+cos2x)+sin2x=\sqrt{3}(1+cosx)[/IMG] [IMG]https://codecogs.izyba.com/png.latex?sin4x-cos4x=1+4(sinx-cosx)[/IMG] [IMG]https://codecogs.izyba.com/png.latex?sin^{4}x+cos^{4}x(x+\frac{\pi }{4})+sin^{4}(x-\frac{\pi }{4})=\frac{9}{8}[/IMG] [IMG]https://codecogs.izyba.com/png.latex?3cos4x-8cos^{6}x+2cos^{2}x+3=0[/IMG] [IMG]https://codecogs.izyba.com/png.latex?sin^{2}(x-\frac{\pi }{4}).tan^{2}x=sin^{2}\frac{x}{2}[/IMG] [IMG]https://codecogs.izyba.com/png.latex?\sqrt{\frac{1}{8cos^{2}x}}=sinx[/IMG] [IMG]https://codecogs.izyba.com/png.latex?\frac{cos^{2}x(cosx-1)}{sinx+cosx}=2(1+sinx)[/IMG] ......................................................... các bạn làm được phần nào thì làm thanks các bạn trước nhe! [/QUOTE]

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