Trả lời chủ đề

4A + O[SUB]2 [/SUB] -> 2A[SUB]2[/SUB]O

x-----1/4.x—1/2.x

 

A[SUB]2[/SUB]O + H[SUB]2[/SUB]O -> 2AOH

1/2.x--1/2.x

 

m [SUB]AOH  [/SUB]= 18g

 

mO[SUB]2 [/SUB] + mH[SUB]2[/SUB]O = 18 – 10,35 =  7,65g

 

<=> x = 7,65/17 = 0,45 mol

 

nO[SUB]2  [/SUB]= 0,45/4 = 0,1125 mol -> V = 0,1125.22,4 = 2,52 lít

 

M[SUB]A [/SUB]= 10,35/0,45 = 23 g/mol --> A là Natri