Tinh do PH

[_]-[aU_]

cho 200ml hon hop gom ( HCL:0.05M va H2SO4:0.025M) Voi 200ml Hon hon gom (NaOH:0.05M va Ba(OH)2 :0.05M):byebye:

 

[sonca009]

cho 200ml hon hop gom ( HCL:0.05M va H2SO4:0.025M) Voi 200ml Hon hon gom (NaOH:0.05M va Ba(OH)2 :0.05M):byebye:

n(H+) = (0,05 + 0,025*2)*0,2 = 0,02 mol
n(OH-)= (0,05+0,05*2)*0,2 = 0,03 mol
Suy ra n(OH-) dư = 0,01 mol => [OH-] = 0,01/0,5=0,02
[H+] = 10^-14/0,02 = 5*10^-13 => pH =12,3!