Đ đặng hoàng ngân New member Xu 0 27/12/11 #1 tìm số tự nhiên n thỏa mãn đẳng thức: (2/5)^n: (3/5)^n+2=100/81
T tuatolala New member Xu 0 18/3/12 #3 (2/3)^n/(3/5)^(n+2)=(2/5)^n*(5/3)^(n+2)=(2^n)/(3^n)*(5^(n+2))/(3^(n+2))=(5/3)^2*(2/3)^n=100/81 nên n=2
(2/3)^n/(3/5)^(n+2)=(2/5)^n*(5/3)^(n+2)=(2^n)/(3^n)*(5^(n+2))/(3^(n+2))=(5/3)^2*(2/3)^n=100/81 nên n=2