tranbaotoan7890
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Giải giúp mình phương trình này:
\[\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}+...+\frac{1}{x^2+15x+56}=\frac{1}{14}\]
\[ \frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{3}{x(x^4+x^2+1)}\]
\[\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}+...+\frac{1}{x^2+15x+56}=\frac{1}{14}\]
\[ \frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{3}{x(x^4+x^2+1)}\]