Normal
B(3+2t; 2+4t; 6+t)C(m,n,k)vectoAC = (m+1, n, k-2)2vectoAB = (8+4t, 4+8t, 8+2t)m+1 = -8 - 4t => m = -9 - 4tn = -4 - 8tk-2 = -8 - 2t => k = -6 - 2tThay vao pt (P): 2(-9 - 4t) - (-4 - 8t) - (-6 - 2t) + 3 = 0 => t = ...dt d qua A nhan vecto AB lam vecto chi phuong => viet ptdt.
B(3+2t; 2+4t; 6+t)
C(m,n,k)
vectoAC = (m+1, n, k-2)
2vectoAB = (8+4t, 4+8t, 8+2t)
m+1 = -8 - 4t => m = -9 - 4t
n = -4 - 8t
k-2 = -8 - 2t => k = -6 - 2t
Thay vao pt (P): 2(-9 - 4t) - (-4 - 8t) - (-6 - 2t) + 3 = 0 => t = ...
dt d qua A nhan vecto AB lam vecto chi phuong => viet ptdt.
