Nội dung mới nhất bởi black_chick

\[I=\int \frac{x^2-3x+5}{\sqrt[7]{(2x+1)^4}}dx \] \[=\frac{1}{8}\int ((2x+1)^2-8(2x+1)+12)(2x+1)^{\frac{-4}{7}}d(2x+1)\] \[=\frac{1}{8}\int (2x+1)^{\frac{10}{7}}-8(2x+1)^{\frac{3}{7}}+12(2x+1)^{\frac{-4}{7}}dx\] \[=...